The reaction of sulphur in alkaline medium is | vedclass

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(C) The reaction is a disproportionation reaction of $S_8$ in an alkaline medium.Reduction half-reaction: $S_8 + 16e^{-} \rightarrow 8S^{2-}$Oxidation

Vedclass · Accepted Answer

$12$

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(C) The reaction is a disproportionation reaction of $S_8$ in an alkaline medium.Reduction half-reaction: $S_8 + 16e^{-} \rightarrow 8S^{2-}$Oxidation half-reaction: $S_8 + 12H_2O \rightarrow 4S_2O_3^{2-} + 24H^{+} + 16e^{-}$Adding both half-reactions: $2S_8 + 12H_2O \rightarrow 8S^{2-} + 4S_2O_3^{2-} + 24H^{+}$To balance in basic medium,add $24OH^{-}$ to both sides:$2S_8 + 12H_2O + 24OH^{-} \rightarrow 8S^{2-} + 4S_2O_3^{2-} + 24H_2O$Simplifying the equation:$2S_8 + 24OH^{-} \rightarrow 8S^{2-} + 4S_2O_3^{2-} + 12H_2O$Dividing by $2$ to get the simplest integer coefficients:$S_8 + 12OH^{-} \rightarrow 4S^{2-} + 2S_2O_3^{2-} + 6H_2O$Comparing this with the given equation,the value of '$a$' is $12$.

The reaction of sulphur in alkaline medium is given below:
$S_{8(s)} + a OH^{-}_{(aq)} \rightarrow b S^{2-}_{(aq)} + c S_{2}{O_{3}}^{2-}_{(aq)} + d H_{2}O_{(\ell)}$
The value of '$a$' is ............ (Integer answer)

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The reaction of sulphur in alkaline medium is given below:$S_{8(s)} + a OH^{-}_{(aq)} \rightarrow b S^{2-}_{(aq)} + c S_{2}{O_{3}}^{2-}_{(aq)} + d H_{2}O_{(\ell)}$The value of '$a$' is ............ (Integer answer)