The reactivities of methyl chloride,propyl ch | vedclass

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Question

(A) The reactivity of alkyl halides towards nucleophilic substitution reactions depends on the stability of the carbocation intermediate (in $S_N1$) o

Vedclass · Accepted Answer

$Methyl$ $chloride$ $>$ $propyl$ $chloride$ $>$ $chlorobenzene$

Vedclass · Answer

(A) The reactivity of alkyl halides towards nucleophilic substitution reactions depends on the stability of the carbocation intermediate (in $S_N1$) or steric hindrance (in $S_N2$).$Methyl$ $chloride$ $(CH_3Cl)$ is a primary halide with minimal steric hindrance,making it highly reactive in $S_N2$ reactions.$Propyl$ $chloride$ $(CH_3CH_2CH_2Cl)$ is also a primary halide but has more steric hindrance than $methyl$ $chloride$,making it slightly less reactive.$Chlorobenzene$ is the least reactive because the $C-Cl$ bond acquires partial double bond character due to resonance,and the $sp^2$ hybridized carbon atom is more electronegative,making the bond shorter and stronger.Therefore,the order of reactivity is: $Methyl$ $chloride$ $>$ $propyl$ $chloride$ $>$ $chlorobenzene$.

The reactivities of $methyl$ $chloride$,$propyl$ $chloride$ and $chlorobenzene$ are in the order:

Similar Questions

Arrange the following halides in decreasing order of $S_N1$ reactivity:
$(I)$ $CH_3CH_2CH_2Cl$
$(II)$ $CH_2=CHCHClCH_3$
$(III)$ $CH_3CH_2CHClCH_3$

$CCl_4 + KOH$ (excess) $\rightarrow$ end product of the reaction is :

Match the following reactions with their mechanisms:
$(A)$ $CH_3CH_2CH_2I \xrightarrow{aq. KOH}$
$(B)$ $(CH_3)_3CCl \xrightarrow{H_2O}$
$(I)$ $S_N1$
$(II)$ $E_2$
$(III)$ $S_N2$
$(IV)$ $E_1$

For the following reactions,which of the following statements is correct?
$A. \, CH_3CH_2CH_2Br + KOH \rightarrow CH_3CH=CH_2 + KBr + H_2O$
$B. \, (CH_3)_2CHBr + KOH \rightarrow (CH_3)_2CHOH + KBr$
$C. \, C_6H_{10} + Br_2 \rightarrow C_6H_{10}Br_2$

Identify the correct decreasing order of ease of dehydrohalogenation of alkyl halides.

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