The reading in the ideal voltmeter (V) shown | vedclass

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(A) Let us traverse the circuit in a clockwise loop.In the top branch, there are $3$ cells of $5 \, V$ each. The positive terminals (longer lines) are

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$5$

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(A) Let us traverse the circuit in a clockwise loop.In the top branch, there are $3$ cells of $5 \, V$ each. The positive terminals (longer lines) are on the left. Traversing from right to left (clockwise), we go from negative to positive, so the $EMF$ is $+3 	imes 5 = +15 \, V$.In the left branch, there is $1$ cell of $5 \, V$. The positive terminal is on the top. Traversing from top to bottom (clockwise), we go from positive to negative, so the $EMF$ is $-5 \, V$.In the bottom branch, there are $3$ cells of $5 \, V$ each. The positive terminals are on the left. Traversing from left to right (clockwise), we go from positive to negative, so the $EMF$ is $-3 	imes 5 = -15 \, V$.In the right branch, there is $1$ cell of $5 \, V$. The positive terminal is on the top. Traversing from bottom to top (clockwise), we go from negative to positive, so the $EMF$ is $+5 \, V$.Total $EMF$ in the loop, $\Sigma E = +15 - 5 - 15 + 5 = 0 \, V$.Since the net $EMF$ is zero, the current in the circuit is $I = 0 \, A$.The ideal voltmeter is connected across the cell in the right branch.The reading of the voltmeter is the terminal voltage of this cell, which is $V = E - Ir$.Since $I = 0$, $V = 5 - 0 = 5 \, V$.

The reading in the ideal voltmeter $(V)$ shown in the given circuit diagram is: (in $V$)

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