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Question

(a)

Weight is the force that gravitational attraction of earth exerts towards the

center of earth=mg

At the equator, an additional centripeta

Vedclass · Accepted Answer

$99.66$

Vedclass · Answer

(a)

Weight is the force that gravitational attraction of earth exerts towards the

center of earth=mg

At the equator, an additional centripetal force acts towards it outside which is equal to

$m \omega^2 R=10 	imes\left(\frac{2 \pi}{ T }ight)^2 	imes\left(6.4 	imes 10^{\circ}ight)=0.33\,N$

Hence, the net force on body at the equator=Recorded weight $=m g-m \omega^2 R=$

$100\,N -0.33\,N =99.66\,N$

The reading of a spring balance corresponds to $100 N$ while situated at the north pole and a body is kept on it. The weight record on the same scale if it is shifted to the equator, is $...........\,N$

(take, $g =10 m / s ^2$ and radius of the earth, $R =6.4 \times 10^3 m$ )

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The reading of a spring balance corresponds to $100 N$ while situated at the north pole and a body is kept on it. The weight record on the same scale if it is shifted to the equator, is $...........\,N$ (take, $g =10 m / s ^2$ and radius of the earth, $R =6.4 \times 10^3 m$ )