The reagent(s) for the following conversion i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The conversion of $1,2-dibromoethane$ to ethyne involves dehydrohalogenation.First,treatment with alcoholic $KOH$ removes one molecule of $HBr$ to

Vedclass · Accepted Answer

alcoholic $KOH$ followed by $NaNH_2$

Vedclass · Answer

(B) The conversion of $1,2-dibromoethane$ to ethyne involves dehydrohalogenation.First,treatment with alcoholic $KOH$ removes one molecule of $HBr$ to form vinyl bromide $(CH_2=CHBr)$.Second,because the $C-Br$ bond in vinyl bromide has partial double bond character due to resonance,it is less reactive towards elimination. Therefore,a stronger base like $NaNH_2$ (sodamide) is required to remove the second molecule of $HBr$ to yield ethyne $(HC \equiv CH)$.Thus,the correct sequence is alcoholic $KOH$ followed by $NaNH_2$.

The reagent$(s)$ for the following conversion is/are:
$Br-CH_2-CH_2-Br \xrightarrow{?} HC \equiv CH$

Similar Questions

Identify the product $D$ in the following series of reaction: $CH_3COOH$ $\xrightarrow{LiAlH_4} A$ $\xrightarrow{H^{+}, 443 \ K} B$ $\xrightarrow{Br_2} C$ $\xrightarrow{alc. KOH} D$

Which of the following is the most acidic substance?

Which of the following reacts with sodium with the elimination of hydrogen?

Hydrogenation of $2-$Butyne in the presence of Lindlar's catalyst gives

What will be the product of the reaction $CH_3-C \equiv C-CH_2CH_3 \xrightarrow[(2) \text{ Hydrolysis}]{(1) O_3} \, ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The reagent$(s)$ for the following conversion is/are:$Br-CH_2-CH_2-Br \xrightarrow{?} HC \equiv CH$