The reagents to carry out the following conve | vedclass

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Question

(D) The starting material is $but-2-yne$ (or $CH_{3}-C \equiv C-CH_{3}$), but the image shows $prop-1-yne$ $(CH_{3}-C \equiv CH)$ being converted to $

Vedclass · Accepted Answer

$NaNH_{2} / CH_{3}I ; HgSO_{4} / dil. \ H_{2}SO_{4}$

Vedclass · Answer

(D) The starting material is $but-2-yne$ (or $CH_{3}-C \equiv C-CH_{3}$), but the image shows $prop-1-yne$ $(CH_{3}-C \equiv CH)$ being converted to $butan-2-one$ $(CH_{3}-CO-CH_{2}-CH_{3})$.Step $1$: $CH_{3}-C \equiv CH + NaNH_{2} \rightarrow CH_{3}-C \equiv C^-Na^+ + NH_{3}$.Step $2$: $CH_{3}-C \equiv C^-Na^+ + CH_{3}I \rightarrow CH_{3}-C \equiv C-CH_{3} + NaI$.Step $3$: $CH_{3}-C \equiv C-CH_{3} + H_{2}O \xrightarrow{HgSO_{4} / dil. H_{2}SO_{4}} CH_{3}-C(OH)=CH-CH_{3}$ (enol form).Step $4$: The enol form undergoes tautomerization to form $CH_{3}-CO-CH_{2}-CH_{3}$ $(butan-2-one)$.Thus, the correct set of reagents is $NaNH_{2} / CH_{3}I ; HgSO_{4} / dil. \ H_{2}SO_{4}$.

The reagents to carry out the following conversion are:

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