The reducing agent used in the following reac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given reaction is the reduction of an ester $(CH_3(CH_2)_9COOC_2H_5)$ to an aldehyde $(CH_3(CH_2)_9CHO)$.$LiAlH_4$ and $NaBH_4$ are strong red

Vedclass · Accepted Answer

$DIBAL-H$

Vedclass · Answer

(D) The given reaction is the reduction of an ester $(CH_3(CH_2)_9COOC_2H_5)$ to an aldehyde $(CH_3(CH_2)_9CHO)$.$LiAlH_4$ and $NaBH_4$ are strong reducing agents that typically reduce esters to primary alcohols.$Pd/H_2$ is a catalyst for hydrogenation,which would reduce the ester to an alcohol or reduce other functional groups if present.$DIBAL-H$ (Diisobutylaluminium hydride) is a selective reducing agent that reduces esters to aldehydes at low temperatures $(-78 \ ^\circ C)$.Therefore,the correct reducing agent is $DIBAL-H$.

The reducing agent used in the following reaction is:

Similar Questions

Lower members of aliphatic carboxylic acids are soluble in water. This is due to

In the reaction,if $X$ is the reagent and $Y$ is the product,which of the following is not feasible?

$X$ is heated with soda lime and gives ethane. $X$ is

Among the following compounds, the one$(s)$ that give$(s)$ effervescence with aqueous $NaHCO_{3}$ solution is (are):
$I. (CH_{3}CO)_{2}O$
$II. CH_{3}COOH$
$III. PhOH$
$IV. CH_{3}COCHO$

Considering the acidity of carboxylic acids:
$(I) PhCOOH$
$(II) o-NO_2C_6H_4COOH$
$(III) p-NO_2C_6H_4COOH$
$(IV) m-NO_2C_6H_4COOH$
What is the correct order of acidic strength?

Vedclass Test Series

Exam Paper Generator

Online Exam Module