The reflecting surface of a plane mirror is v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the mirror be in the $yz$-plane. The particle is moving in the $xy$-plane. The horizontal component of the velocity is $v_x = v \cos(60^\circ)

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(A) Let the mirror be in the $yz$-plane. The particle is moving in the $xy$-plane. The horizontal component of the velocity is $v_x = v \cos(60^\circ) = 10 	imes 0.5 = 5 \, m/s$ towards the mirror.For a plane mirror,the velocity of the image $v_i$ is related to the velocity of the object $v_o$ by the relation $v_{ix} = -v_{ox}$ (assuming the mirror is stationary).Here,the object velocity component towards the mirror is $v_{ox} = 5 \, m/s$.Therefore,the velocity of the image component towards the mirror is $v_{ix} = -5 \, m/s$ (the negative sign indicates it is moving away from the mirror in the coordinate system,but relative to the mirror,the image moves towards it).The velocity of approach between the object and its image is given by $v_{app} = v_{ox} - v_{ix} = 5 - (-5) = 10 \, m/s$.

Similar Questions

$A$ light ray is incident perpendicular to the plane of a mirror. The angle of reflection will be ......$^o$.

What are the types of mirrors?

$A$ light beam is being reflected by using two mirrors,as in a periscope used in submarines. If one of the mirrors rotates by an angle $\theta$,the reflected light will deviate from its original path by the angle

An object is initially at a distance of $100 \; cm$ from a plane mirror. If the mirror approaches the object at a speed of $10 \; cm/s$,then after $6 \; s$,the distance between the object and its image will be: (in $; cm$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module