The refractive index of a transparent liquid filled in an equilateral hollow prism is $\sqrt{2}$. The angle of minimum deviation for the liquid will be (in $^{\circ}$)

$A$ ray is incident at an angle of incidence $i$ on one surface of a small angle prism (with angle of prism $A$) and emerges normally from the opposite surface. If the refractive index of the material of the prism is $\mu$,then the angle of incidence is nearly equal to

If a thin prism of glass is dipped into water,then the minimum deviation (with respect to air) of light produced by the prism will be: $\left( {_a{\mu _g} = \frac{3}{2} \text{ and } _a{\mu _w} = \frac{4}{3}} \right)$

$A$ ray is incident at an angle of $53^{\circ}$ on a prism and emerges at an angle of $37^{\circ}$ as shown. If the angle of incidence is changed to $50^{\circ}$,which of the following is a possible value of the angle of emergence (in $^{\circ}$)?

How is the graph between the angle of deviation $(\delta)$ and the angle of incidence $(i)$ represented for a triangular prism?

Assertion: There exist two angles of incidence for the same magnitude of deviation (except for minimum deviation) by a prism kept in air.
Reason: In a prism kept in air,a ray is incident on the first surface and emerges out of the second surface. If another ray is incident on the second surface along the path of the previous emergent ray,then this ray emerges out of the first surface along the path of the previous incident ray. This principle is called the principle of reversibility of light.