The refractive index of glass is $1.5$ and that of water is $1.33$. The critical angle for a ray of light going from glass to water is
- A$\sin ^{-1}\left(\frac{4}{7}\right)$
- B$\sin ^{-1}\left(\frac{5}{8}\right)$
- C$\sin ^{-1}\left(\frac{8}{9}\right)$
- D$\sin ^{-1}\left(\frac{2}{3}\right)$
Explore More
Similar Questions
$A$ diver at a depth of $12 \ m$ in water $\left(\mu = \frac{4}{3}\right)$ sees the sky in a cone of semi-vertical angle:
$A$ small bulb is placed at the bottom of a tank containing water to a depth of $80 \, cm$. What is the area of the surface of water through which light from the bulb can emerge out? The refractive index of water is $1.33$. (Consider the bulb to be a point source.)
Difficult
View SolutionExplain the principle,construction,and working of an optical fibre.
Medium
View Solution$A$ light ray falls on a rectangular glass slab as shown in the figure. If total internal reflection occurs at the vertical face of the slab at point $B$,the refractive index of glass is
$A$ fish inside water sees the outside world through a circular horizon. If the refractive index of water is $4/3$ and the fish is $12 \, cm$ below the water surface,then the radius of this circle is $= ..... cm$.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo