The relation between the permittivity of free space $(\epsilon_0)$, the permeability of free space $(\mu_0)$, and the speed of light $(c)$ is:

$A$ plane electromagnetic wave of wavelength $3.0 \ m$ travels in vacuum along the positive $X$-axis. The electric field of amplitude $300 \ Vm^{-1}$ oscillates parallel to the $Y$-axis. Then the intensity of the wave is $(\mu_0 = 4\pi \times 10^{-7} \ Hm^{-1}, c = 3 \times 10^8 \ ms^{-1})$ (in $Wm^{-2}$)

The electric field of an electromagnetic wave in free space is represented as $\vec{E} = E_0 \cos(\omega t - kz) \hat{i}$. The corresponding magnetic induction vector will be:

In an electromagnetic wave in free space,the root mean square value of the electric field is $E_{rms} = 6 \, V m^{-1}$. The peak value of the magnetic field is:

In an electromagnetic wave,the phase difference between the electric and magnetic field vectors $\vec{E}$ and $\vec{B}$ is:

Even though an electric field $E$ exerts a force $qE$ on a charged particle, the electric field of an $EM$ wave does not contribute to the radiation pressure (but transfers energy). Explain.