The resistance of a conductivity cell of $0.1 \ M$ $KCl$ solution is $120 \ \Omega$ and conductivity is $1.64 \times 10^{-4} \ S \ cm^{-1}$. What is the value of cell constant (in $cm^{-1}$)?

What benefit do we get by forming a thin layer of $Pt$ particles on the electrodes of a conductivity cell?

The dissociation constant of acetic acid is $1.75 \times 10^{-5}$ and $\Lambda _{CH_3COOH}^o = 370.6 \times 10^{-4} \, S \, m^2 \, mol^{-1}$. The specific conductance of $0.01 \, M$ acetic acid solution will be:

At $25^oC$,the molar conductance of a $0.1 \ M$ aqueous solution of ammonium hydroxide is $9.54 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and at infinite dilution,its molar conductance is $238 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. The degree of ionization of ammonium hydroxide at the same concentration and temperature is ........... $\%$.

The resistivity of a $0.8 \ M$ solution of an electrolyte is $5 \times 10^{-3} \ \Omega \ cm$. Its molar conductivity is $..... \times 10^4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. (Nearest integer)

Resistance of a decimolar solution between two electrodes $0.02 \ m$ apart and $0.0004 \ m^2$ in area was found to be $50 \ \Omega$. Specific conductance $(\kappa)$ is $:$