The resistance of a germanium junction diode | vedclass

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(B) The resistance of the diode is given by the reciprocal of the slope of the $V-I$ characteristic curve in the forward bias region.From the graph,th

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$0.2$

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(B) The resistance of the diode is given by the reciprocal of the slope of the $V-I$ characteristic curve in the forward bias region.From the graph,the knee voltage $V_k = 0.3 \, V$.The current $I = 10 \, mA = 10 	imes 10^{-3} \, A$ at a voltage $V = 2.3 \, V$.The dynamic resistance $R$ is calculated as:$R = \frac{\Delta V}{\Delta I} = \frac{V - V_k}{I - 0}$$R = \frac{2.3 \, V - 0.3 \, V}{10 	imes 10^{-3} \, A - 0}$$R = \frac{2.0 \, V}{10 	imes 10^{-3} \, A} = 0.2 	imes 10^3 \, \Omega = 200 \, \Omega$.Converting to $k\Omega$,we get $R = 0.2 \, k\Omega$.

The resistance of a germanium junction diode whose $V-I$ characteristic is shown in the figure is ........ $k\Omega$ $(V_k = 0.3 \, V)$.

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