The resolving power of an astronomical telesc | vedclass

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Question

(B) The resolving power $(RP)$ of a telescope is given by the formula $RP = \frac{D}{1.22\,\lambda}$,where $D$ is the diameter of the objective lens a

Vedclass · Accepted Answer

$0.2$

Vedclass · Answer

(B) The resolving power $(RP)$ of a telescope is given by the formula $RP = \frac{D}{1.22\,\lambda}$,where $D$ is the diameter of the objective lens and $\lambda$ is the wavelength of light.Since the resolving power is directly proportional to the diameter of the objective lens $(RP \propto D)$,covering the central half portion of the objective lens does not change the effective diameter $D$ of the aperture that contributes to the resolution of the image.However,in standard physics problems of this type,if the diameter $D$ remains unchanged,the resolving power remains constant.Therefore,the resolving power remains $0.2\, sec$.

The resolving power of an astronomical telescope is $0.2\, sec$. If the central half portion of the objective lens is covered,the resolving power will be....$sec$

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