The result after adding 3.8 times 10^{-6} and | vedclass

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Question

(C) To add these numbers,we first express them with the same power of $10$: $3.8 	imes 10^{-6} = 0.38 	imes 10^{-5}$ Now,add the numbers: $0.38 	im

Vedclass · Accepted Answer

$4.6 	imes 10^{-5}$

Vedclass · Answer

(C) To add these numbers,we first express them with the same power of $10$: $3.8 	imes 10^{-6} = 0.38 	imes 10^{-5}$ Now,add the numbers: $0.38 	imes 10^{-5} + 4.2 	imes 10^{-5} = (0.38 + 4.2) 	imes 10^{-5} = 4.58 	imes 10^{-5}$ According to the rules of significant figures for addition,the result should be reported to the same number of decimal places as the measurement with the fewest decimal places. $0.38$ has two decimal places and $4.2$ has one decimal place. Therefore,the result must be rounded to one decimal place. Rounding $4.58$ to one decimal place gives $4.6$. Thus,the final result is $4.6 	imes 10^{-5}$.

Column-$I$	Column-$II$
$(1)$ $2.85 \times 10^{26} \ kg$	$(a)$ $1$
$(2)$ $0.009 \ m^2$	$(b)$ $2$
$(3)$ $0.060 \ s$	$(c)$ $3$

The result after adding $3.8 \times 10^{-6}$ and $4.2 \times 10^{-5}$ with due regard to significant figures is:

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Column-$I$ Column-$II$

$(1)$ $2.85 \times 10^{26} \ kg$ $(a)$ $1$

$(2)$ $0.009 \ m^2$ $(b)$ $2$

$(3)$ $0.060 \ s$ $(c)$ $3$

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