The role of fluorspar (CaF_2), which is added | vedclass

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(C) In the Hall-Heroult process, pure alumina $(Al_2O_3)$ has a very high melting point and is a poor conductor of electricity. To overcome these issu

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to lower the melting temperature of the mixture

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(C) In the Hall-Heroult process, pure alumina $(Al_2O_3)$ has a very high melting point and is a poor conductor of electricity. To overcome these issues, it is dissolved in molten cryolite $(Na_3AlF_6)$. Fluorspar $(CaF_2)$ is added in small quantities to the mixture to lower the melting point of the electrolyte and to increase its electrical conductivity. Therefore, both $(b)$ and $(c)$ are correct roles of fluorspar.

The role of fluorspar $(CaF_2)$, which is added in small quantities in the electrolytic reduction of alumina $(Al_2O_3)$ dissolved in fused cryolite $(Na_3AlF_6)$, is:

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