The same quantity of electricity was passed t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Faraday's law of electrolysis,the mass deposited $(W)$ is given by $W = \frac{M 	imes Q}{n 	imes F}$,where $M$ is the atomic mass,$

Vedclass · Accepted Answer

$1, 3, 2$

Vedclass · Answer

(C) According to Faraday's law of electrolysis,the mass deposited $(W)$ is given by $W = \frac{M 	imes Q}{n 	imes F}$,where $M$ is the atomic mass,$Q$ is the quantity of electricity,$n$ is the valency,and $F$ is Faraday's constant.Since $Q$ and $F$ are constant,$W \propto \frac{M}{n}$,which implies $n \propto \frac{M}{W}$.For element $X$: $n_X \propto \frac{7}{2.1} = 3.33$.For element $Y$: $n_Y \propto \frac{27}{2.7} = 10$.For element $Z$: $n_Z \propto \frac{48}{7.2} = 6.66$.The ratio of valencies $n_X : n_Y : n_Z = 3.33 : 10 : 6.66$.Dividing by $3.33$,we get the ratio $1 : 3 : 2$.

The same quantity of electricity was passed through solutions of salts of elements $X$,$Y$,and $Z$ with atomic masses $7$,$27$,and $48$ respectively. The masses of $X$,$Y$,and $Z$ deposited were $2.1 \ g$,$2.7 \ g$,and $7.2 \ g$ respectively. The valencies of $X$,$Y$,and $Z$ respectively are:

Similar Questions

$38.6 \ A$ of current is passed for $100 \ s$ through an aqueous $CuSO_4$ solution using platinum electrodes. The mass of copper deposited from the solution and the volume of gas liberated at $STP$ are respectively (molar mass of $Cu = 63.54 \ g \ mol^{-1}$)

For the electrolytic decomposition of $18 \ g$ of $H_2O$,how many hours of current at $3 \ A$ must be passed?

How long should aqueous $NaCl$ be electrolysed by passing $100 \ A$ current,so that $0.5 \ mol$ chlorine is released at anode?

During electrolysis of fused aluminium chloride,$0.9 \ g$ of aluminium was deposited on the cathode. The volume of chlorine liberated at the anode will be .............. $litres$ (at $STP$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module