The self-inductance of a coil having 500 turn | vedclass

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Question

(A) The magnetic flux $\phi$ linked with a coil is given by the relation $\phi = L 	imes I$,where $L$ is the self-inductance and $I$ is the current f

Vedclass · Accepted Answer

$4 	imes 10^{-4}\,Wb$

Vedclass · Answer

(A) The magnetic flux $\phi$ linked with a coil is given by the relation $\phi = L 	imes I$,where $L$ is the self-inductance and $I$ is the current flowing through the coil.Given:Self-inductance $L = 50\,mH = 50 	imes 10^{-3}\,H$Current $I = 8\,mA = 8 	imes 10^{-3}\,A$Substituting the values into the formula:$\phi = (50 	imes 10^{-3}\,H) 	imes (8 	imes 10^{-3}\,A)$$\phi = 400 	imes 10^{-6}\,Wb$$\phi = 4 	imes 10^{-4}\,Wb$Therefore,the correct option is $A$.

The self-inductance of a coil having $500$ turns is $50\,mH$. The magnetic flux through the cross-sectional area of the coil when the current through it is $8\,mA$ is found to be:

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