The set of quantum numbers for the $19^{th}$ electron in chromium $(Cr)$ is:

  • A
    $n = 4, l = 0, m = 0, s = +1/2 \text{ or } -1/2$
  • B
    $n = 3, l = 2, m = 1, s = +1/2 \text{ or } -1/2$
  • C
    $n = 3, l = 2, m = -1, s = +1/2 \text{ or } -1/2$
  • D
    $n = 4, l = 1, m = 0, s = +1/2 \text{ or } -1/2$

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Similar Questions

Which of the following statements are correct?
$(a)$ When an electron in an atom moves from $n=4$ to $n=2$,it gains energy.
$(b)$ An electron in a $3p$ orbital would have less energy than an electron in a $2p$ orbital.
$(c)$ $A$ $3s$ subshell has a maximum of $2$ electrons.
$(d)$ $A$ $3^{rd}$ orbit may contain a maximum of $10$ electrons.

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