(B) From the figure,the shaded region is bounded by the vertical lines $x = -3$ and $x = 3$.Since the lines $x = -3$ and $x = 3$ are solid lines,the p

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(B) From the figure,the shaded region is bounded by the vertical lines $x = -3$ and $x = 3$.Since the lines $x = -3$ and $x = 3$ are solid lines,the points on these lines are included in the region.Thus,the region represents all $x$ such that $-3 \leq x \leq 3$.This inequality can be written in terms of the absolute value as $|x| \leq 3$.

Class 11 Mathematics Linear Inequalities Linear inequalities for Single Line

Easy

The shaded region given in the figure represents the $\ldots \ldots \ldots$ inequality.

A
$|x| < 3$
B
$|x| \leq 3$
C
$|x| > 3$
D
$-3 < x \leq 3$

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Linear inequalities for Single Line

Solve the following inequality graphically in a two-dimensional plane: $2x + y > 3$.

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Solve the following inequality graphically in a two-dimensional plane: $4x - y > 0$.

Easy

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Solve the following system of inequalities:
$8x + 3y \leq 100$ $(1)$
$x \geq 0$ $(2)$
$y \geq 0$ $(3)$

Medium

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Solve $7x + 3 < 5x + 9$. Show the graph of the solutions on a number line.

Easy

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Solve the given inequality graphically in a two-dimensional plane: $-3x + 2y \geq -6$.

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The shaded region given in the figure represents the $\ldots \ldots \ldots$ inequality.

Similar Questions

Solve the following inequality graphically in a two-dimensional plane: $2x + y > 3$.

Solve the following inequality graphically in a two-dimensional plane: $4x - y > 0$.

Solve the following system of inequalities:$8x + 3y \leq 100$ $(1)$$x \geq 0$ $(2)$$y \geq 0$ $(3)$

Solve $7x + 3 < 5x + 9$. Show the graph of the solutions on a number line.

Solve the given inequality graphically in a two-dimensional plane: $-3x + 2y \geq -6$.

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Solve the following system of inequalities:
$8x + 3y \leq 100$ $(1)$
$x \geq 0$ $(2)$
$y \geq 0$ $(3)$