The shape of a lump of jaggery is that of a f | vedclass

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(B) The volume of a frustum of a cone is given by the formula: $V = \frac{1}{3} \pi h (r_1^2 + r_2^2 + r_1 r_2)$.Given: $r_1 = 14 \, cm$,$r_2 = 7 \, c

Vedclass · Accepted Answer

$4312$

Vedclass · Answer

(B) The volume of a frustum of a cone is given by the formula: $V = \frac{1}{3} \pi h (r_1^2 + r_2^2 + r_1 r_2)$.Given: $r_1 = 14 \, cm$,$r_2 = 7 \, cm$,and $h = 12 \, cm$.Substituting the values into the formula:$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 12 	imes (14^2 + 7^2 + 14 	imes 7)$$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 12 	imes (196 + 49 + 98)$$V = \frac{1}{3} 	imes \frac{22}{7} 	imes 12 	imes (343)$$V = 22 	imes 4 	imes 49 = 4312 \, cm^3$.

The shape of a lump of jaggery is that of a frustum of a cone. Its radii are $14 \, cm$ and $7 \, cm$ and height is $12 \, cm$. Find the volume of the lump of jaggery (in $cm^3$).

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