The shape of a molecule of $NH_3$,in which the central atom contains a lone pair of electrons,is

Match List-$I$ with List-$II$ :

List-$I$ (Compound / Species)	List-$II$ (Shape / Geometry)
$A$. $SF_4$	$I$. Tetrahedral
$B$. $BrF_3$	$II$. Pyramidal
$C$. $BrO_3^{-}$	$III$. See-saw
$D$. $NH_4^{+}$	$IV$. Bent $T$-shape

Choose the correct answer from the options given below :

Among the following species,which two have a trigonal pyramidal shape?
$I. NI_3$ $II. I_3^-$
$III. SO_3^{2-}$ $IV. NO_3^-$

The correct increasing order of adjacent bond angle among $BF_3$,$PF_3$,and $ClF_3$ is:

According to Lewis theory, the total number of bond-pairs and lone pairs of electrons around the central atom of $XeO_6^{4-}$ ion is . . . . . . .

Identify the incorrect match between the electron geometry and the possible molecular shape derived from it:

Electron geometry	Possible molecular shape