The shape of the $XeF_4$ molecule is:

The number of molecule$(s)$ or ion$(s)$ from the following having non-planar structure is
$NO_{3}^{-}, H_{2}O_{2}, BF_{3}, PCl_{3}, XeF_{4}, SF_{4}, XeO_{3}, PH_{4}^{+}, SO_{3}, [Al(OH)_{4}]^{-}$

Which of the following compounds has the smallest bond angle $(X-A-X)$ in each series respectively?

$A$. $OSF_2, OSCl_2, OSBr_2$

$B$. $SbCl_3, SbBr_3, SbI_3$

$C$. $PI_3, AsI_3, SbI_3$

The number of lone pairs of electrons on the central atom of $SCl_2$,$O_3$,$ClF_3$,and $SF_6$,respectively,are:

Match $List-I$ with $List-II$.

$List-I$ (Compound)	$List-II$ (Shape)
$A$. $BrF_5$	$I$. bent
$B$. $[CrF_6]^{3-}$	$II$. square pyramidal
$C$. $O_3$	$III$. trigonal bipyramidal
$D$. $PCl_5$	$IV$. octahedral

Choose the correct answer from the options given below.

The molecular shapes of $SF_4$,$CF_4$,and $XeF_4$ are