The shortest distance between the lines $r=(-2 \hat{i}+\hat{j}-\hat{k})+r(2 \hat{i}+3 \hat{j}-\hat{k})$ and $r=(\hat{i}-\hat{j}+2 \hat{k})+k(-\hat{i}+2 \hat{j}+4 \hat{k})$ is

  • A
    $0$
  • B
    $\frac{10}{\sqrt{6}}$
  • C
    $\frac{11}{\sqrt{6}}$
  • D
    $\frac{13}{\sqrt{6}}$

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