(D) Given sides are $a=3, b=5, c=3$. Using the Law of Cosines: $\cos A = \frac{b^2 + c^2 - a^2}{2bc}$. Substituting the values: $\cos A = \frac{5^2 +

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(D) Given sides are $a=3, b=5, c=3$. Using the Law of Cosines: $\cos A = \frac{b^2 + c^2 - a^2}{2bc}$. Substituting the values: $\cos A = \frac{5^2 + 3^2 - 3^2}{2 \times 5 \times 3}$. $\cos A = \frac{25 + 9 - 9}{30} = \frac{25}{30}$. $\cos A = \frac{5}{6}$.

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

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The sides of a $\triangle ABC$ are given by $a=3, b=5$ and $c=3$. Then,$\cos A=$

AP EAMCET 2022 All AP EAMCET

A
$2/6$
B
$1/6$
C
$2/3$
D
$5/6$

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Trigonometrical Equations

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Relation between sides and angles, Solutions of triangles

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