(C) To find the simplest formula,we calculate the mole ratio of the elements:Moles of $X = \frac{50}{10} = 5 \text{ mol}$Moles of $Y = \frac{50}{20} =

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(C) To find the simplest formula,we calculate the mole ratio of the elements:Moles of $X = \frac{50}{10} = 5 \text{ mol}$Moles of $Y = \frac{50}{20} = 2.5 \text{ mol}$Now,divide by the smallest number of moles to get the simplest ratio:Ratio of $X : Y = \frac{5}{2.5} : \frac{2.5}{2.5} = 2 : 1$Therefore,the simplest formula is $X_2Y$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

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The simplest formula of a compound containing $50\%$ of element $X$ (at. wt. $= 10$) and $50\%$ of element $Y$ (at. wt. $= 20$) is

A
$X_2Y_3$
B
$XY_2$
C
$X_2Y$
D
$XY$

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Some Basic Concepts of Chemistry

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Percentage composition and Molecular formula

The empirical formula of a carbohydrate is $CH_2O$. If $0.1 \, \text{mol}$ of this carbohydrate contains $1 \, g$ of hydrogen,what is its molecular formula?

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An organic compound with $C = 40\%$ and $H = 6.7\%$ will have the empirical formula

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Calculate the mass percent of different elements present in sodium sulphate $(Na_{2}SO_{4})$.

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Define Percentage Composition in a compound.

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An organic compound contains $60\ \%\ C$, $4.48\ \%\ H$, and $35.5\ \%\ O$. Its empirical formula is:

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The simplest formula of a compound containing $50\%$ of element $X$ (at. wt. $= 10$) and $50\%$ of element $Y$ (at. wt. $= 20$) is

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The empirical formula of a carbohydrate is $CH_2O$. If $0.1 \, \text{mol}$ of this carbohydrate contains $1 \, g$ of hydrogen,what is its molecular formula?

An organic compound with $C = 40\%$ and $H = 6.7\%$ will have the empirical formula

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