The simplification of 1+frac{1}{2+frac{1}{1-f | vedclass

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Question

(C) To simplify the expression $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$,we solve from the bottom up.First,simplify the denominator of the lowest fracti

Vedclass · Accepted Answer

$\frac{9}{7}$

Vedclass · Answer

(C) To simplify the expression $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$,we solve from the bottom up.First,simplify the denominator of the lowest fraction: $1-\frac{1}{3} = \frac{3-1}{3} = \frac{2}{3}$.Now,the expression becomes $1+\frac{1}{2+\frac{1}{2/3}}$.Next,simplify the term $\frac{1}{2/3}$,which is $\frac{3}{2}$.Now,the expression becomes $1+\frac{1}{2+\frac{3}{2}}$.Simplify the denominator $2+\frac{3}{2} = \frac{4+3}{2} = \frac{7}{2}$.Finally,the expression becomes $1+\frac{1}{7/2} = 1+\frac{2}{7} = \frac{7+2}{7} = \frac{9}{7}$.

The simplification of $1+\frac{1}{2+\frac{1}{1-\frac{1}{3}}}$ yields the result

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