The size of the species Pb,Pb^{2+},and Pb^{4+ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For a given element,the neutral atom $(Pb)$ has th

Vedclass · Accepted Answer

$Pb > Pb^{2+} > Pb^{4+}$

Vedclass · Answer

(B) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For a given element,the neutral atom $(Pb)$ has the largest size because it has the most electrons and the least effective nuclear charge per electron. When electrons are removed to form cations ($Pb^{2+}$ and $Pb^{4+}$),the remaining electrons experience a greater effective nuclear charge,causing the electron cloud to be pulled closer to the nucleus. Therefore,as the positive charge on the ion increases,the ionic radius decreases. Thus,the order of size is $Pb > Pb^{2+} > Pb^{4+}$.

The size of the species $Pb$,$Pb^{2+}$,and $Pb^{4+}$ decreases as:

Similar Questions

Describe the theory associated with the radius of an atom as it:
$(a)$ Gains an electron
$(b)$ Loses an electron

Which of the following represents the incorrect order of ionic or atomic radii?

Which of the following has the smallest size?

The ions $S^{2-}, Cl^{-}, K^{+}, Ca^{2+}$ are isoelectronic. Their ionic radii show

The order of increasing ionic radius of the following is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module