The sodium fusion extract is boiled with concentrated nitric acid while testing for halogens. By doing so,it

Match the organic compounds in column $I$ with the Lassaigne's test results in column $II$ appropriately.

Column $I$	Column $II$
$A$. Aniline	$i$. Red colour with $FeCl_3$
$B$. Benzene sulfonic acid	$ii$. Violet colour with sodium nitroprusside
$C$. Thiourea	$iii$. Blue colour with hot and acidic solution of $FeSO_4$

For testing halogens in an organic compound with $AgNO_{3}$ solution,sodium extract (Lassaigne's test) is acidified with dilute $HNO_{3}$. What will happen if a student acidifies the extract with dilute $H_{2}SO_{4}$ in place of dilute $HNO_{3}$?

Match the compounds in List-$I$ with the observations in List-$II$,and choose the correct option.

List-$I$	List-$II$
$I$. Aniline	$P$. Sodium fusion extract of the compound on boiling with $FeSO_4$,followed by acidification with conc. $H_2SO_4$,gives Prussian blue color.
$II$. $o$-Cresol	$Q$. Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
$III$. Cysteine	$R$. Addition of the compound to a saturated solution of $NaHCO_3$ results in effervescence.
$IV$. Caprolactam	$S$. The compound reacts with bromine water to give a white precipitate.
	$T$. Treating the compound with neutral $FeCl_3$ solution produces violet color.

The Lassaigne's extract is boiled with dilute $HNO_3$ before testing for halogens because,

Given below are two statements :
Statement $I$ : Nitrogen,sulphur,halogen and phosphorus present in an organic compound are detected by Lassaigne's Test.
Statement $II$ : The elements present in the compound are converted from covalent form into ionic form by fusing the compound with Magnesium in Lassaigne's test.
In the light of the above statements,choose the correct answer from the options given below :