The solubility of $AgI$ in $NaI$ solution is less than that in pure water because

  • A
    $AgI$ forms a complex with $NaI$
  • B
    Of common ion effect
  • C
    Solubility product of $AgI$ is less than that of $NaI$
  • D
    The temperature of the solution decreases

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When $NH_4Cl$ is added to $NH_4OH$ solution,the dissociation of $NH_4OH$ is reduced. This is due to:

Statement $A$: Addition of $NH_4OH$ in the presence of excess $NH_4Cl$ to an aqueous solution of $BaCl_2$ results in the precipitation of $Ba(OH)_2$.
Reason $R$: $Ba(OH)_2$ is insoluble in water.

Solubility of $AgCl$ in conc. $HCl$ is ...... than in water.

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