The solubility of calcium carbonate $(CaCO_3)$ at $298 \ K$ is $6.4 \times 10^{-5} \ mol \ dm^{-3}$. Calculate the value of solubility product $(K_{sp})$ at the same temperature.
- A$5.06 \times 10^{-10}$
- B$4.096 \times 10^{-9}$
- C$3.05 \times 10^{-10}$
- D$2.8 \times 10^{-9}$
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