The solution from the following with the highest depression in freezing point (lowest freezing point) is:

  • A
    $180 \ g$ of acetic acid dissolved in water
  • B
    $180 \ g$ of acetic acid dissolved in benzene
  • C
    $180 \ g$ of benzoic acid dissolved in benzene
  • D
    $180 \ g$ of glucose dissolved in water

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The $pH$ of a $0.1 \, M$ monobasic acid is measured to be $2$. Its osmotic pressure at a given temperature $T \, K$ is (in $, RT$)

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For a dilute solution containing $2.5 \ g$ of a non-volatile non-electrolyte solute in $100 \ g$ of water,the elevation in boiling point at $1 \ atm$ pressure is $2^{\circ} C$. Assuming the concentration of solute is much lower than the concentration of solvent,the vapour pressure ($mm$ of $Hg$) of the solution is (take $K_{b}=0.76 \ K \ kg \ mol^{-1}$)

The difference between the boiling point and freezing point of an aqueous solution of urea containing $10.0 \ kg$ of water is $100.2372 \ ^oC$. How many grams of urea are dissolved in the solution? (Given: $K_b = 0.513 \ K \ kg \ mol^{-1}$,$K_f = 1.86 \ K \ kg \ mol^{-1}$)

$A$ solution containing $1.8 \ g$ of a compound (empirical formula $CH_2O$) in $40 \ g$ of water is observed to freeze at $-0.465 \ ^oC$. The molecular formula of the compound is ($K_f$ of water $= 1.86 \ K \ kg \ mol^{-1}$)

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