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(C) Speed and time are inversely proportional to each other when the distance is constant.Given the ratio of speeds $v_1 : v_2 : v_3 = 1 : 3 : 5$.The

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$15: 5: 3$

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(C) Speed and time are inversely proportional to each other when the distance is constant.Given the ratio of speeds $v_1 : v_2 : v_3 = 1 : 3 : 5$.The time taken $t$ is given by $t = \frac{d}{v}$.Since the distance $d$ is the same for all three cars,the ratio of time taken is $t_1 : t_2 : t_3 = \frac{1}{v_1} : \frac{1}{v_2} : \frac{1}{v_3}$.Substituting the values,we get $t_1 : t_2 : t_3 = \frac{1}{1} : \frac{1}{3} : \frac{1}{5}$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of $1, 3,$ and $5$,which is $15$.Ratio $= (1 	imes 15) : (\frac{1}{3} 	imes 15) : (\frac{1}{5} 	imes 15) = 15 : 5 : 3$.

The speeds of three cars are in the ratio of $1: 3: 5$. The ratio among the time taken by these cars to travel the same distance is

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