The spin magnetic moment of cobalt in the com | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the compound $Hg[Co(SCN)_4]$,the oxidation state of $Co$ is $+2$.$Co^{2+}$ has an electronic configuration of $[Ar] 3d^7$.$SCN^-$ is a weak fie

Vedclass · Accepted Answer

$\sqrt{15}$

Vedclass · Answer

(C) In the compound $Hg[Co(SCN)_4]$,the oxidation state of $Co$ is $+2$.$Co^{2+}$ has an electronic configuration of $[Ar] 3d^7$.$SCN^-$ is a weak field ligand,so it forms a tetrahedral complex.In a tetrahedral field,the $d$-orbitals split into $e$ and $t_2$ sets.The configuration for $d^7$ in a tetrahedral field is $e^4 t_2^3$.This results in $n = 3$ unpaired electrons.The spin magnetic moment $\mu_s$ is calculated using the formula $\mu_s = \sqrt{n(n+2)} \ BM$.Substituting $n = 3$: $\mu_s = \sqrt{3(3+2)} = \sqrt{3 	imes 5} = \sqrt{15} \ BM$.

The spin magnetic moment of cobalt in the compound $Hg[Co(SCN)_4]$ is

Similar Questions

The wavelength of the first line in the Balmer series in the hydrogen spectrum is $\lambda$. What is the wavelength of the second line?

$A$ magnetic needle lying parallel to a magnetic field is turned through $60^{\circ}$. The work done on it is $W$. The torque required to maintain the magnetic needle in the position mentioned above is

The base current in a transistor circuit changes from $45 \mu A$ to $140 \mu A$. Accordingly,the collector current changes from $0.2 \text{ mA}$ to $4.0 \text{ mA}$. The current gain is

Assertion : For a reaction $2NH_{3(g)} \to N_{2(g)} + 3H_{2(g)}$ ; $\Delta H > \Delta E$
Reason : Enthalpy change is always greater than internal energy change.

Which type of glass is used in the manufacturing of lenses and prisms?

Vedclass Test Series

Exam Paper Generator

Online Exam Module