The square root of 134 + sqrt{6292} is | vedclass

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(B) We need to find the square root of $134 + \sqrt{6292}$.First,simplify $\sqrt{6292} = \sqrt{4 	imes 1573} = 2\sqrt{1573} = 2\sqrt{121 	imes 13} =

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$11 + \sqrt{13}$

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(B) We need to find the square root of $134 + \sqrt{6292}$.First,simplify $\sqrt{6292} = \sqrt{4 	imes 1573} = 2\sqrt{1573} = 2\sqrt{121 	imes 13} = 2 	imes 11 \sqrt{13} = 22\sqrt{13}$.Now,the expression is $134 + 22\sqrt{13}$.We want to write this in the form $(a + b)^2 = a^2 + b^2 + 2ab$.Let $a = 11$ and $b = \sqrt{13}$.Then $a^2 + b^2 = 11^2 + (\sqrt{13})^2 = 121 + 13 = 134$.And $2ab = 2 	imes 11 	imes \sqrt{13} = 22\sqrt{13}$.Thus,$134 + 22\sqrt{13} = 11^2 + (\sqrt{13})^2 + 2(11)(\sqrt{13}) = (11 + \sqrt{13})^2$.Therefore,$\sqrt{134 + \sqrt{6292}} = \sqrt{(11 + \sqrt{13})^2} = 11 + \sqrt{13}$.

The square root of $134 + \sqrt{6292}$ is

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