The stability of $Me_2C=CH_2$ is more than that of $MeCH_2CH=CH_2$ due to

  • A
    inductive effect of the $Me$ groups
  • B
    resonance effect of the $Me$ groups
  • C
    hyperconjugative effect of the $Me$ groups
  • D
    resonance as well as inductive effect of the $Me$ groups

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Similar Questions

Assertion $(A)$: Reaction of $but-1-ene$ with $HBr$ gives $1-bromobutane$ as the major product.
Reason $(R)$: Addition of $HBr$ to unsymmetrical alkenes proceeds according to Markovnikov's rule.
The correct answer is

$HCl$ does not follow the anti-Markovnikov rule because...

The product $(P)$ is:

Suppose the following reaction,the major product will be:

Consider the following reaction:
$Alkene (A) \xrightarrow{KMnO_4, \Delta} CH_3CH_2COCH_3 + CH_3CH_2CH_2CH_2COOH$
$A$ is:

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