The standard enthalpies of combustion of C_6H | vedclass

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(B) We are given the following combustion reactions:$C_6H_{6(l)} + \frac{15}{2}O_{2(g)} 	o 6CO_{2(g)} + 3H_2O_{(l)}$; $\Delta H = -3270 \ kJ \ mol^{-

Vedclass · Accepted Answer

$+48$

Vedclass · Answer

(B) We are given the following combustion reactions:$C_6H_{6(l)} + \frac{15}{2}O_{2(g)} 	o 6CO_{2(g)} + 3H_2O_{(l)}$; $\Delta H = -3270 \ kJ \ mol^{-1} \dots (i)$$C(gr) + O_{2(g)} 	o CO_{2(g)}$; $\Delta H = -394 \ kJ \ mol^{-1} \dots (ii)$$H_{2(g)} + \frac{1}{2}O_{2(g)} 	o H_2O_{(l)}$; $\Delta H = -286 \ kJ \ mol^{-1} \dots (iii)$We need to find the enthalpy of formation of $C_6H_{6(l)}$:$6C(gr) + 3H_{2(g)} 	o C_6H_{6(l)}$; $\Delta H_f = ? \dots (iv)$By performing the operation $6 	imes (ii) + 3 	imes (iii) - (i)$,we get:$\Delta H_f = [6 	imes (-394) + 3 	imes (-286)] - (-3270)$$\Delta H_f = [-2364 - 858] + 3270$$\Delta H_f = -3222 + 3270 = +48 \ kJ \ mol^{-1}$

The standard enthalpies of combustion of $C_6H_{6(l)}$,$C(graphite)$ and $H_{2(g)}$ are respectively $-3270 \ kJ \ mol^{-1}$,$-394 \ kJ \ mol^{-1}$ and $-286 \ kJ \ mol^{-1}$. What is the standard enthalpy of formation of $C_6H_{6(l)}$ in $kJ \ mol^{-1}$?

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