The state of hybridisation of B in BCl_3 is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The atomic number of Boron $(B)$ is $5$. Its ground state electronic configuration is $1s^2 2s^2 2p^1$.In the excited state,one electron from the

Vedclass · Accepted Answer

$sp^2$

Vedclass · Answer

(B) The atomic number of Boron $(B)$ is $5$. Its ground state electronic configuration is $1s^2 2s^2 2p^1$.In the excited state,one electron from the $2s$ orbital is promoted to the $2p$ orbital,resulting in the configuration $1s^2 2s^1 2p_x^1 2p_y^1$.These three orbitals $(2s, 2p_x, 2p_y)$ undergo $sp^2$ hybridisation to form three equivalent $sp^2$ hybrid orbitals.These three $sp^2$ hybrid orbitals overlap with the $3p$ orbitals of three $Cl$ atoms to form three $B-Cl$ bonds.Therefore,the hybridisation of $B$ in $BCl_3$ is $sp^2$.

The state of hybridisation of $B$ in $BCl_3$ is

Similar Questions

In which of the following sets of molecules is the hybridisation of the central atoms different?

Describe hybridization in the case of $PCl_5$ and $SF_6$. The axial bonds are longer as compared to equatorial bonds in $PCl_5$ whereas in $SF_6$ both axial bonds and equatorial bonds have the same bond length. Explain.

The hybridisation of $S$ in $SF_{4}$ is

$X$ and $Y$ are two covalent molecules in which the hybridization of the central atoms is the same,but their shapes are different. $X$ and $Y$ are:

Which type of hybridisation occurs in ethylene?

Vedclass Test Series

Exam Paper Generator

Online Exam Module