(A) The maximum current $(I_{\max})$ that can be drawn from a battery is obtained when the external resistance is zero (short circuit condition).Using

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(A) The maximum current $(I_{\max})$ that can be drawn from a battery is obtained when the external resistance is zero (short circuit condition).Using Ohm's law for a circuit,$I = \frac{\varepsilon}{R + r}$.For maximum current,$R = 0$,so $I_{\max} = \frac{\varepsilon}{r}$.Given: $\varepsilon = 12 \ V$ and $r = 0.6 \ \Omega$.$I_{\max} = \frac{12}{0.6} = \frac{120}{6} = 20 \ A$.Therefore,the correct option is $A$.

Class 12 Physics Current Electricity Circuit Solving for current and Voltage

Easy

The storage battery of a car has an emf of $12 \ V$. If the internal resistance of the battery is $0.6 \ \Omega$,then the maximum current that can be drawn from the battery is . . . . . . . (in $A$)

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A
$20$
B
$30$
C
$25$
D
$75$

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The storage battery of a car has an emf of $12 \ V$. If the internal resistance of the battery is $0.6 \ \Omega$,then the maximum current that can be drawn from the battery is . . . . . . . (in $A$)

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$A$ current of $2.0 \, A$ passes through a cell of $e.m.f.$ $1.5 \, V$ having an internal resistance of $0.15 \, \Omega$. The potential difference measured,in $volts$,across the terminals of the cell will be:

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