The successive ionization energies of an elem | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The successive ionization energies are $IE_1 = 20 \ eV, IE_2 = 45 \ eV, IE_3 = 150 \ eV, IE_4 = 900 \ eV, IE_5 = 1800 \ eV$. There is a large jump

Vedclass · Accepted Answer

$AX_3$

Vedclass · Answer

(B) The successive ionization energies are $IE_1 = 20 \ eV, IE_2 = 45 \ eV, IE_3 = 150 \ eV, IE_4 = 900 \ eV, IE_5 = 1800 \ eV$. There is a large jump in ionization energy between $IE_3$ and $IE_4$ $(900 - 150 = 750 \ eV)$. This indicates that the fourth electron is being removed from a stable noble gas core,meaning the element $(A)$ has $3$ valence electrons. Therefore,the stable oxidation state of $(A)$ is $+3$. Thus,the formula of the halide of $(A)$ is $AX_3$.

The successive ionization energies of an element $(A)$ are given as $IE_1 = 20 \ eV, IE_2 = 45 \ eV, IE_3 = 150 \ eV, IE_4 = 900 \ eV, IE_5 = 1800 \ eV$. What is the formula of the halide of $(A)$?

Similar Questions

Select the gas-phase reaction$(s)$ which can proceed spontaneously?

Outermost electronic configurations of four elements $A, B, C, D$ are given below:
$A: 3s^{2}$
$B: 3s^{2} 3p^{1}$
$C: 3s^{2} 3p^{3}$
$D: 3s^{2} 3p^{4}$
The correct order of first ionization enthalpy for them is:

What is the correct order of the first ionization energy for $Li, Be, B,$ and $Na$?

$A$ large difference between the fourth and fifth ionization energies indicates the presence of

The $1^{st}$ ionization enthalpy for $Mg$ is $+737 \text{ kJ/mol}$. The most probable estimated value of the $2^{nd}$ ionization enthalpy of $Mg$ is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module