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(D) The reaction of methane with iodine is a reversible process: $CH_4 + I_2 \rightleftharpoons CH_3I + HI$. Since $HI$ is a strong reducing agent,it

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$I_2, HNO_3$

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(D) The reaction of methane with iodine is a reversible process: $CH_4 + I_2 \rightleftharpoons CH_3I + HI$. Since $HI$ is a strong reducing agent,it reduces $CH_3I$ back to $CH_4$. To drive the reaction in the forward direction,an oxidizing agent like $HNO_3$ is added to consume $HI$ and convert it back into $I_2$: $2HNO_3 + 2HI \longrightarrow 2NO_2 + 2H_2O + I_2$. Therefore,$I_2$ and $HNO_3$ are the suitable reagents.

The suitable reagents for the conversion of methane into methyl iodide are

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