(A) $1$. In $Fe(CO)_5$,the oxidation state of $Fe$ is $0$ because $CO$ is a neutral ligand.$2$. In $VO^{2+}$,let the oxidation state of $V$ be $x$. Th

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(A) $1$. In $Fe(CO)_5$,the oxidation state of $Fe$ is $0$ because $CO$ is a neutral ligand.$2$. In $VO^{2+}$,let the oxidation state of $V$ be $x$. Then $x + (-2) = +2$,so $x = +4$.$3$. In $WO_3$,let the oxidation state of $W$ be $y$. Then $y + 3(-2) = 0$,so $y = +6$.$4$. The sum of the oxidation states $= 0 + 4 + 6 = 10$.