The sum of oxidation states of all atoms in $Cr_{2}O_{7}^{2-}$ ion is

  • A
    Zero
  • B
    $-2$
  • C
    $2$
  • D
    $+6$

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$1$. The oxidation number of hydrogen is always $+1$.
$2$. The algebraic sum of all the oxidation numbers of all elements in a compound is zero.
$3$. An element in the free or the uncombined state bears oxidation number zero.
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