The sum of three numbers is 98. If the ratio | vedclass

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(B) Let the three numbers be $I, II,$ and $III$.Given $I + II + III = 98$.The ratios are $I : II = 2 : 3$ and $II : III = 5 : 8$.To combine these rati

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$30$

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(B) Let the three numbers be $I, II,$ and $III$.Given $I + II + III = 98$.The ratios are $I : II = 2 : 3$ and $II : III = 5 : 8$.To combine these ratios,we make the value of $II$ common in both ratios.Multiply the first ratio by $5$ and the second ratio by $3$:$I : II = (2 	imes 5) : (3 	imes 5) = 10 : 15$$II : III = (5 	imes 3) : (8 	imes 3) = 15 : 24$Thus,the combined ratio is $I : II : III = 10 : 15 : 24$.Let the numbers be $10x, 15x,$ and $24x$.Sum $= 10x + 15x + 24x = 49x$.Given $49x = 98$,so $x = 98 / 49 = 2$.The second number is $15x = 15 	imes 2 = 30$.

The sum of three numbers is $98$. If the ratio of the first to the second is $2:3$ and that of the second to the third is $5:8$,then the second number is:

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