The sum of three numbers is 264. If the first | vedclass

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(C) Let the second number be $x$.According to the problem:First number $= 2x$Third number $= \frac{1}{3} 	imes (2x) = \frac{2}{3}x$The sum of the thr

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$72$

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(C) Let the second number be $x$.According to the problem:First number $= 2x$Third number $= \frac{1}{3} 	imes (2x) = \frac{2}{3}x$The sum of the three numbers is $264$,so:$2x + x + \frac{2}{3}x = 264$Combine the terms:$3x + \frac{2}{3}x = 264$$\frac{9x + 2x}{3} = 264$$\frac{11x}{3} = 264$Solve for $x$:$11x = 264 	imes 3$$11x = 792$$x = \frac{792}{11} = 72$Therefore,the second number is $72$.

The sum of three numbers is $264$. If the first number is twice the second and the third number is one-third of the first,then the second number is:

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