The sum of two numbers is frac{23}{20} of the | vedclass

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(C) Let the two numbers be $x$ and $y$.According to the problem,the sum of the two numbers is $\frac{23}{20}$ of the first number $(x)$:$x + y = \frac

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) Let the two numbers be $x$ and $y$.According to the problem,the sum of the two numbers is $\frac{23}{20}$ of the first number $(x)$:$x + y = \frac{23}{20}x$Subtract $x$ from both sides to find the second number $(y)$:$y = \frac{23}{20}x - x$$y = \frac{23x - 20x}{20} = \frac{3x}{20}$To find what percent the second number is of the first,calculate $\frac{y}{x} 	imes 100$:$	ext{Percentage} = \left( \frac{\frac{3x}{20}}{x} ight) 	imes 100$$	ext{Percentage} = \frac{3}{20} 	imes 100 = 3 	imes 5 = 15 \%$

The sum of two numbers is $\frac{23}{20}$ of the first number. The second number is what percent of the first?

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