The sun subtends an angle of (1/2)^o at the s | vedclass

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(B) The angular diameter of the sun is given as $	heta = (1/2)^o$.To use this in the formula,we convert it to radians:$	heta = (1/2) 	imes (\pi / 1

Vedclass · Accepted Answer

$9$

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(B) The angular diameter of the sun is given as $	heta = (1/2)^o$.To use this in the formula,we convert it to radians:$	heta = (1/2) 	imes (\pi / 180) \, 	ext{radians} = \pi / 360 \, 	ext{radians}$.The focal length of the converging lens is $f = 100 \, cm = 1 \, m$.The diameter of the image $d_I$ formed at the focal plane is given by the relation:$d_I = f 	imes 	heta$$d_I = 100 \, cm 	imes (1/2) 	imes (\pi / 180) \, 	ext{radians}$$d_I = 100 	imes (1/2) 	imes (3.14159 / 180) \, cm$$d_I \approx 0.8726 \, cm$Converting to millimeters:$d_I \approx 8.726 \, mm \approx 9 \, mm$.Thus,the diameter of the image formed is about $9 \, mm$.

The sun subtends an angle of $(1/2)^o$ at the surface of the earth. $A$ converging lens of focal length $100\, cm$ is used to obtain an image of the sun on a screen. The diameter of the image formed is about.....$mm$.

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