The surface tension of $70 \text{ dynes/cm}$ is equal to:

$A$ rectangular film of liquid is expanded from $(5 \text{ cm} \times 4 \text{ cm})$ to $(7 \text{ cm} \times 8 \text{ cm})$. If the work done is $3 \times 10^{-4} \text{ J}$,the surface tension of the liquid is (nearly):

Oil spreads over the surface of water whereas water does not spread over the surface of the oil,due to

$A$ square wire frame of each side $L$ is dipped in soap solution. On taking out, a membrane is formed. If the surface tension of the solution is $T$, the force acting on the frame will be (in $T L$)

$A$ square frame of side $L$ is dipped in a liquid. On taking out,a membrane is formed. If the surface tension of the liquid is $T$,the force acting on the frame will be (in $TL$)

Arrange the following liquids in increasing order of surface tension: Water,Mercury,Soap solution.