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(C) First, convert the temperatures from Celsius to Kelvin:$T_1 = 127 + 273 = 400 \ K$$T_2 = 227 + 273 = 500 \ K$$T_0 = 27 + 273 = 300 \ K$According t

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$3.1$

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(C) First, convert the temperatures from Celsius to Kelvin:$T_1 = 127 + 273 = 400 \ K$$T_2 = 227 + 273 = 500 \ K$$T_0 = 27 + 273 = 300 \ K$According to the Stefan-Boltzmann law, the net energy emitted per second by a body is given by:$E = \varepsilon \sigma A (T^4 - T_0^4)$Therefore, the ratio of energies is:$\frac{E_2}{E_1} = \frac{T_2^4 - T_0^4}{T_1^4 - T_0^4}$Substituting the values:$\frac{E_2}{E_1} = \frac{500^4 - 300^4}{400^4 - 300^4}$$\frac{E_2}{E_1} = \frac{625 	imes 10^8 - 81 	imes 10^8}{256 	imes 10^8 - 81 	imes 10^8}$$\frac{E_2}{E_1} = \frac{544}{175} \approx 3.108$Thus, the ratio is approximately $3.1$.

The temperature of a body is increased from $T_1 = 127^{\circ}C$ to $T_2 = 227^{\circ}C$. The ambient temperature is $T_0 = 27^{\circ}C$. The energies emitted per second by the body at $T_1$ and $T_2$ are $E_1$ and $E_2$ respectively. The ratio of $\frac{E_2}{E_1}$ is:

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