The temperature of the hot and cold ends of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a thermal steady state,the temperature gradient along a uniform rod is constant.The temperature gradient is given by: $\frac{dT}{dx} = \frac{T_

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(B) In a thermal steady state,the temperature gradient along a uniform rod is constant.The temperature gradient is given by: $\frac{dT}{dx} = \frac{T_{hot} - T_{cold}}{L} = \frac{100^\circ C - 20^\circ C}{20 \ cm} = \frac{80}{20} = 4^\circ C/cm$.The temperature at any distance $x$ from the hot end is given by $T(x) = T_{hot} - (	ext{gradient} 	imes x)$.At the centre of the rod,$x = 10 \ cm$.Therefore,$T(10) = 100^\circ C - (4^\circ C/cm 	imes 10 \ cm) = 100^\circ C - 40^\circ C = 60^\circ C$.

The temperature of the hot and cold ends of a $20 \ cm$ long rod in a thermal steady state are at $100^\circ C$ and $20^\circ C$ respectively. The temperature at the centre of the rod is ...... $^\circ C$.

Similar Questions

Four rods of silver,copper,brass,and wood are of the same shape. They are heated together after wrapping a paper on each. The paper will burn first on:

When two ends of a rod wrapped with cotton are maintained at different temperatures and after some time every point of the rod attains a constant temperature,then

If it takes $7 \, h$ to form a $1 \, cm$ thick layer of ice on a pond at $0^o C$,how many hours will it take for the thickness of the ice layer to increase from $1 \, cm$ to $2 \, cm$?

Two thin blankets keep more warmth than one blanket of thickness equal to these two. The reason is

Why are snow particles poorer conductors of heat than ice?

Vedclass Test Series

Exam Paper Generator

Online Exam Module